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LAST UPDATED: 20 Nov, 2022
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$\begingroup$ Dear @RenéG, you even do not need to use Solve. Equation x^2 + y^2 == r^2 is not necessary, it is a combination of the last two. Finally, if you substitute r in the las two, you already have the solution I posted. Your task could be done by hand. I just only wanted to show the way of applying CoordinateTransform for more complex cases. You should have ...
https://mathematica.stackexchange.com/questions/160821/use-solve-to-convert-polar-to-cartesian-coordinatesCalculus. Calculus questions and answers. Convert the polar equation to a Cartesian equation . Then use a Cartesian coordinate system to graph the Cartesian equation . r cos theta = 4 The Cartesian equation for r cos theta = 4 is (Type an equation .) Question: Convert the polar equation to a Cartesian equation .
https://www.chegg.com/homework-help/questions-and-answers/convert-polar-equation-cartesian-equation-use-cartesian-coordinate-system-graph-cartesian--q23068053To convert from polar to rectangular coordinates, use the trigonometric ratios and where r is the hypotenuse of the right triangle. The rectangular form of the polar coordinate (r, θ) is (rcos θ, rsin θ). To convert from rectangular to polar coordinates, use the Pythagorean Theorem and the trigonometric ratio.
Locate the angle on the polar coordinate plane. Refer to the figure to find the angle: Determine where the radius intersects the angle. Because the radius is 2 (r = 2), you start at the pole and move out 2 spots in the direction of the angle. Plot the given point.
To convert from polar to rectangular, find the real component by multiplying the polar magnitude by the cosine of the angle, and the imaginary component by multiplying the polar magnitude by the sine of the angle.
The graph of a polar equation is the set of all points in the plane whose polar coordinates (at least one representation) satisfy the equation. The graph of the polar equation r = 1 consists of those points in the plane whose distance from the pole is 1. That is the circle of radius 1 centered at the pole.
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